0-1-4x-3-d-2-dx-2-1-x-2-5-dx- Tinku Tara June 3, 2023 Integration 0 Comments FacebookTweetPin Question Number 4957 by ankit chakravarti last updated on 26/Mar/16 ∫014x3{d2dx2(1−x2)5}dx=? Commented by ankit chakravarti last updated on 26/Mar/16 pleasesolve….. Answered by Yozzii last updated on 26/Mar/16 IntegratingbypartsweobtainI=∫014x3{d2dx2(1−x2)5}dxI=4x3ddx(1−x2)5∣01−∫0112x2(ddx(1−x2)5)dxI=0−12([x2(1−x2)5]01−∫012x(1−x2)5dx)I=(−12)∫01(−2x)(1−x2)5dxLetu=1−x2⇒du=−2xdx⇒I=−12∫10u5du=12∫01u5du=126u6∣01=2. Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: solve-y-3-2y-2-y-x-sinx-Next Next post: calculate-lim-x-0-ln-x-sinx-x-2- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.