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0-1-e-2arctg-t-2-dt-




Question Number 143477 by ArielVyny last updated on 14/Jun/21
∫_0 ^1 e^(2arctg(t^2 )) dt
$$\int_{\mathrm{0}} ^{\mathrm{1}} {e}^{\mathrm{2}{arctg}\left({t}^{\mathrm{2}} \right)} {dt} \\ $$

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