0-1-e-x-ln-x-dx-

Question Number 131166 by SEKRET last updated on 02/Feb/21

\int_{0}^{+ \infty} \frac{1}{e^{x} \cdot \ln (x)} dx = ?

Commented by Dwaipayan Shikari last updated on 02/Feb/21

D i v e r g e n t

I f \int_{0}^{\infty} e^{- x} l o g (x) d x = - γ

Commented by mnjuly1970 last updated on 02/Feb/21

o k \dots t h a n k s a l o t \dots