0-a-x-4-e-x-e-x-1-2-dt-please-solve-this-

Question Number 135824 by Khakie last updated on 16/Mar/21

\int_{0}^{a} \frac{x^{4} e^{x}}{{(e^{x} - 1)}^{2}} d t

p l e a s e s o l v e t h i s \dots

Commented by mathmax by abdo last updated on 16/Mar/21

i think the Q is \int_{0}^{a} \frac{x^{4} e^{x}}{{(e^{x} - 1)}^{2}} dx . .

Answered by Ñï= last updated on 16/Mar/21

\int_{0}^{a} \frac{x^{4} e^{x}}{{(e^{x} - 1)}^{2}} d t = \frac{x^{4} e^{x}}{{(e^{z} - 1)}^{2}} t ∣_{0}^{a} = \frac{x^{4} e^{x}}{{(e^{x} - 1)}^{2}} a

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