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0-pi-2-sin-x-cos-x-dx-




Question Number 132798 by metamorfose last updated on 16/Feb/21
∫_0 ^(π/2) ((√(sin (x)))+(√(cos (x))))dx
π20(sin(x)+cos(x))dx
Answered by Ñï= last updated on 17/Feb/21
∫_0 ^(π/2) ((√(sinx))+(√(cosx)))dx  =B((3/4),(1/2))  =((Γ((3/4))Γ((1/2)))/(Γ((5/4))))  =4(√π)((Γ((3/4)))/(Γ((1/4))))
0π2(sinx+cosx)dx=B(34,12)=Γ(34)Γ(12)Γ(54)=4πΓ(34)Γ(14)
Answered by Dwaipayan Shikari last updated on 16/Feb/21
∫_0 ^(π/2) (√(sin(x)))+(√(cos(x))) dx       =((Γ((3/4))Γ((1/2)))/(Γ((5/4))))=((4(√2)π)/(Γ^2 ((1/4))))
0π2sin(x)+cos(x)dx=Γ(34)Γ(12)Γ(54)=42πΓ2(14)

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