0-pi-2-sin-x-cos-x-dx- Tinku Tara June 3, 2023 Integration 0 Comments FacebookTweetPin Question Number 132798 by metamorfose last updated on 16/Feb/21 ∫π20(sin(x)+cos(x))dx Answered by Ñï= last updated on 17/Feb/21 ∫0π2(sinx+cosx)dx=B(34,12)=Γ(34)Γ(12)Γ(54)=4πΓ(34)Γ(14) Answered by Dwaipayan Shikari last updated on 16/Feb/21 ∫0π2sin(x)+cos(x)dx=Γ(34)Γ(12)Γ(54)=42πΓ2(14) Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: Question-67254Next Next post: dx-1-x-4-1-2-dx-1-ix-2-1-2-dx-1-ix-2-1-2-e-i-pi-4-d-e-i-pi-4-x-1-e-i-pi-4-x-2-1-2-e-i-pi-4-d-e-i-pi-4-x-1-e-i-pi-4-x-2-1-2-e-i-pi-4-ta Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.