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0-pi-cos-4-x-sin-x-dx-




Question Number 134219 by Raxreedoroid last updated on 01/Mar/21
∫_0 ^( π) cos^4  x sin x dx=?
0πcos4xsinxdx=?
Answered by liberty last updated on 01/Mar/21
=−[(1/5)cos^5 x ]_0 ^π =−(1/5)[−1−1]=(2/5)
=[15cos5x]0π=15[11]=25

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