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0-sin-x-log-2-x-x-dx-pi-24-12-2-pi-2-




Question Number 138967 by mnjuly1970 last updated on 20/Apr/21
 Θ=∫_0 ^( ∞) ((sin(x).log^2 (x))/x)dx=(π/(24))(12 γ^( 2) +π^2 )....✓
Θ=0sin(x).log2(x)xdx=π24(12γ2+π2).
Answered by Dwaipayan Shikari last updated on 20/Apr/21
χ(μ)=∫_0 ^∞ ((sinx)/x^μ )dx=(π/(2Γ(μ)sin(((πμ)/2))))  χ′′(1)=∫_0 ^∞ ((sinx)/x)log^2 (x)dx=(π/2)((π^2 /(12))+γ^2 )
χ(μ)=0sinxxμdx=π2Γ(μ)sin(πμ2)χ(1)=0sinxxlog2(x)dx=π2(π212+γ2)

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