0-x-1-2-x-1-ln-2-x-1-dx-pi-2ln-2-2-

Tinku Tara June 3, 2023 None 0 Comments

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Question Number 137941 by Ñï= last updated on 08/Apr/21

∫_0 ^∞ ((x−1)/( (√(2^x −1))ln (2^x −1)))dx=(π/(2ln^2 2))

\int_{0}^{\infty} \frac{x - 1}{\sqrt{2^{x} - 1} l n (2^{x} - 1)} d x = \frac{π}{2 {l n}^{2} 2}

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