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1-1-2pi-2-2-1-1-pi-2-2-1-1-1-pi-2-2-1-1-2pi-2-2-csc-2-1-pi-pi-2-




Question Number 135647 by Dwaipayan Shikari last updated on 14/Mar/21
...+(1/((1−2π^2 )^2 ))+(1/((1−π^2 )^2 ))+1+(1/((1+π^2 )^2 ))+(1/((1+2π^2 )^2 ))+...=((csc^2 ((1/π)))/π^2 )
+1(12π2)2+1(1π2)2+1+1(1+π2)2+1(1+2π2)2+=csc2(1π)π2

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