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1-2-3-3-3-2-4-3-3-5-3-4-6-3-5-




Question Number 135170 by bramlexs22 last updated on 11/Mar/21
1+(2/3)+(3/3^2 )+(4/3^3 )+(5/3^4 )+(6/3^5 )+... =?
$$\mathrm{1}+\frac{\mathrm{2}}{\mathrm{3}}+\frac{\mathrm{3}}{\mathrm{3}^{\mathrm{2}} }+\frac{\mathrm{4}}{\mathrm{3}^{\mathrm{3}} }+\frac{\mathrm{5}}{\mathrm{3}^{\mathrm{4}} }+\frac{\mathrm{6}}{\mathrm{3}^{\mathrm{5}} }+…\:=?\: \\ $$$$ \\ $$
Answered by bemath last updated on 11/Mar/21

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