1-2-3-4-n-n-n-1-2-1-2-2-2-3-2-n-2-n-n-1-2n-1-6-1-x-2-x-3-x-n-x-Formula-x-R-

Question Number 9232 by geovane10math last updated on 24/Nov/16

1 + 2 + 3 + 4 + \dots + n = \frac{n (n + 1)}{2}

1^{2} + 2^{2} + 3^{2} + \dots + n^{2} = \frac{n (n + 1) (2 n + 1)}{6}

1^{x} + 2^{x} + 3^{x} + \dots + = n^{x} = Formula ?

x \in R

Commented by sou1618 last updated on 25/Nov/16

Commented by sou1618 last updated on 25/Nov/16

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