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1-4×2-1-2x-13-0-

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Question Number 73358 by 07032041818 last updated on 10/Nov/19
1/4x2−1/2x−13=0
1/4x2−1/2x−13=0
Commented by MJS last updated on 10/Nov/19
it′s not clear whether you mean (1/4)x^2 −(1/2)x−13=0 in this case ×4 x^2 −2x−52=0 x=1±(√(53)) or you mean (1/(4x^2 ))−(1/(2x))−13=0 in this case ×(−4x^2 )/52 x^2 +(1/(26))x−(1/(52))=0 x=−(1/(52))±((√(53))/(52))
it′snotclearwhetheryoumean14x2−12x−13=0inthiscase×4x2−2x−52=0x=1±53oryoumean14x2−12x−13=0inthiscase×(−4x2)/52x2+126x−152=0x=−152±5352

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