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1-ln-x-dx-




Question Number 132110 by Raxreedoroid last updated on 11/Feb/21
∫(1/(ln x))dx=?
1lnxdx=?
Answered by Olaf last updated on 11/Feb/21
F(x) = ∫(dx/(lnx))  Let x = e^u   F(e^u ) = ∫((d(e^u ))/(ln(e^u ))) = ∫(e^u /u)du = Ei(u)  u = lnx  F(x) = Ei(lnx) (+C)
F(x)=dxlnxLetx=euF(eu)=d(eu)ln(eu)=euudu=Ei(u)u=lnxF(x)=Ei(lnx)(+C)
Commented by Raxreedoroid last updated on 11/Feb/21
What is Ei?
WhatisEi?
Commented by Olaf last updated on 11/Feb/21
Ei(x) = ∫_(−∞) ^x (e^t /t)dt  (integral exponential function)
Ei(x)=xettdt(integralexponentialfunction)

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