Question Number 11766 by uni last updated on 31/Mar/17
$$\int\frac{\mathrm{1}}{\mathrm{sin2x}}\mathrm{dx}=? \\ $$
Answered by ajfour last updated on 31/Mar/17
$$\int\:\frac{{dx}}{\mathrm{2sin}\:{x}\mathrm{cos}\:{x}}=\frac{\mathrm{1}}{\mathrm{2}}\int\:\frac{\mathrm{sec}\:^{\mathrm{2}} {x}}{\mathrm{tan}\:{x}}\:{dx} \\ $$$$=\frac{\mathrm{1}}{\mathrm{2}}\mathrm{ln}\:\mid\mathrm{tan}\:{x}\mid+{C} \\ $$