2-pi-e-17-16-pi-4e-82-81-pi-9e-257-256-pi-16e-

Question Number 133988 by Dwaipayan Shikari last updated on 26/Feb/21

(2 + \frac{π}{e}) (\frac{17}{16} + \frac{π}{4 e}) (\frac{82}{81} + \frac{π}{9 e}) (\frac{257}{256} + \frac{π}{16 e}) \dots

Commented by Olaf last updated on 26/Feb/21

P = \underset{n = 1}{\prod^{\infty}} (\frac{? + 1}{?} + \frac{π}{n^{2} e})

\dots I {c a n}^{'} t f i n d t h e s e q u e n c e \dots

\dots n o t e n o u g h d a t a \dots

Commented by Dwaipayan Shikari last updated on 26/Feb/21

\underset{n = 1}{\prod^{\infty}} (1 + \frac{1}{n^{4}} + \frac{π}{{e n}^{2}}) . S o r r y i h a v e e d i t e d