2-pi-sec-2-x-tan-2-x-dx-

Question Number 8807 by tawakalitu last updated on 28/Oct/16

\int_{2}^{π} (\sec^{2} x - \tan^{2} x) dx

Answered by ridwan balatif last updated on 29/Oct/16

remember : \tan^{2} x = \sec^{2} x - 1 \Leftrightarrow \sec^{2} x - \tan^{2} x = 1

\underset{2}{\int^{π}} (\sec^{2} x - \tan^{2} x) dx = \underset{2}{\int^{π}} 1 dx = x \underset{2}{\overset{π}{∣}} = π - 2

Commented by tawakalitu last updated on 29/Oct/16

Thank you sir . God bless you .