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25-1-log-2-a-1-5-1-log-4-a-3-a-0-5-Simplify-




Question Number 5023 by love math last updated on 03/Apr/16
((25^(−1) + log_2 a^(−1) )/(5^(−1) −log_4 a))−(3/a^(−0.5) )    Simplify
251+log2a151log4a3a0.5Simplify
Answered by Rasheed Soomro last updated on 05/Apr/16
((25^(−1) + log_2 a^(−1) )/(5^(−1) −log_4 a))−(3/a^(−0.5) )  log_2 a^(−1) =((log_5 a^(−1) )/(log_5 2))     log_4 a=((log_5 a)/(log_5 4))  25^(−1) =log_5 x⇒x=5^(25^(−1) )   5^(−1) =log_5 x⇒x=5^5^(−1)    ((25^(−1) + log_2 a^(−1) )/(5^(−1) −log_4 a))−(3/a^(−0.5) )=((log_5 (5^(25^(−1) ) )+((log_5 a^(−1) )/(log_5 2)))/(log_5 (5^5^(−1)  )−((log_5 a)/(log_5 4))))−(3/a^(−0.5) )  =((log_5 (5^(25^(−1) ) )log_5 2+log_5 a^(−1) )/(log_5 2))×((log_5 4)/(log_5 (5^5^(−1)  )log_5 4−log_5 a))−(3/a^(−0.5) )  ((log_5 (5^(25^(−log_5 2) ) )+log_5 a^(−1) )/(log_5 (5^5^(−log_5 ^ 4)  )−log_5 a))×((log_5 4)/(log_5 2))−(3/a^(−0.5) )  ((log_5 (5^(25^(−log_5 2) ) ×a^(−1) ))/(log_5 (5^5^(−log_5 ^ 4)  ÷log_5 a)))×((log_5 4)/(log_5 2))−(3/a^(−0.5) )  Too complicated,I can′t continue.
251+log2a151log4a3a0.5log2a1=log5a1log52log4a=log5alog54251=log5xx=525151=log5xx=551251+log2a151log4a3a0.5=log5(5251)+log5a1log52log5(551)log5alog543a0.5=log5(5251)log52+log5a1log52×log54log5(551)log54log5a3a0.5log5(525log52)+log5a1log5(55log54)log5a×log54log523a0.5log5(525log52×a1)log5(55log54÷log5a)×log54log523a0.5Toocomplicated,Icantcontinue.
Answered by Rasheed Soomro last updated on 05/Apr/16
((25^(−1) + log_2 a^(−1) )/(5^(−1) −log_4 a))−(3/a^(−0.5) )  ((1−25log_2 a)/(25))×(5/(1−5log_4 a))−3(√a)  ((1−25log_2 a)/(5−25log_4 a))−3(√a)  ((1−25log_2 a)/(5−25(((log_2 a)/(log_2 4)))))−3(√a)  ((1−25log_2 a)/(5−25(((log_2 a)/2))))−3(√a)  ((1−25log_2 a)/(5−((25)/2)log_2 a))−3(√a)
251+log2a151log4a3a0.5125log2a25×515log4a3a125log2a525log4a3a125log2a525(log2alog24)3a125log2a525(log2a2)3a125log2a5252log2a3a

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