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3-log-2-3-x-1-2-log-3-2-x-1-1-




Question Number 136064 by bramlexs22 last updated on 18/Mar/21
     3^(log _2 (3^x −1))  = 2^(log _3 (2^x +1)) + 1
$$\:\:\:\:\:\mathrm{3}^{\mathrm{log}\:_{\mathrm{2}} \left(\mathrm{3}^{{x}} −\mathrm{1}\right)} \:=\:\mathrm{2}^{\mathrm{log}\:_{\mathrm{3}} \left(\mathrm{2}^{{x}} +\mathrm{1}\right)} +\:\mathrm{1} \\ $$
Answered by Kintinu last updated on 18/Mar/21
    answer: x=1
$$\:\:\:\:\mathrm{answer}:\:\mathrm{x}=\mathrm{1} \\ $$
Commented by bramlexs22 last updated on 18/Mar/21
how
$${how} \\ $$

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