Question Number 136064 by bramlexs22 last updated on 18/Mar/21
$$\:\:\:\:\:\mathrm{3}^{\mathrm{log}\:_{\mathrm{2}} \left(\mathrm{3}^{{x}} −\mathrm{1}\right)} \:=\:\mathrm{2}^{\mathrm{log}\:_{\mathrm{3}} \left(\mathrm{2}^{{x}} +\mathrm{1}\right)} +\:\mathrm{1} \\ $$
Answered by Kintinu last updated on 18/Mar/21
$$\:\:\:\:\mathrm{answer}:\:\mathrm{x}=\mathrm{1} \\ $$
Commented by bramlexs22 last updated on 18/Mar/21
$${how} \\ $$