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3a-b-c-d-2014-3b-a-c-d-2014-3c-a-b-d-2014-3d-a-b-c-2014-Find-all-the-solution-of-a-b-c-d-if-a-b-c-d-R-




Question Number 9523 by Joel575 last updated on 12/Dec/16
3a = (b + c + d)^(2014)   3b = (a + c + d)^(2014)   3c = (a + b + d)^(2014)   3d = (a + b + c)^(2014)   Find all the solution of (a, b, c, d) if a, b, c, d ∈ R
3a=(b+c+d)20143b=(a+c+d)20143c=(a+b+d)20143d=(a+b+c)2014Findallthesolutionof(a,b,c,d)ifa,b,c,dR
Answered by mrW last updated on 16/Dec/16
let u=a+b+c+d  ⇒3a=(u−a)^(2014)   ⇒3b=(u−b)^(2014)   ⇒3c=(u−c)^(2014)   ⇒3d=(u−d)^(2014)   ⇒a=b=c=d=x  3x=(3x)^(2014)   ⇒x=0  ⇒(3x)^(2013) =1  ⇒3x=^(2013) (√1)=1  ⇒x=(1/3)
letu=a+b+c+d3a=(ua)20143b=(ub)20143c=(uc)20143d=(ud)2014a=b=c=d=x3x=(3x)2014x=0(3x)2013=13x=20131=1x=13

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