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3x-2y-4z-2-3y-4z-2-2y-6z-1-




Question Number 6251 by net last updated on 20/Jun/16
3x−2y−4z=2  3y−4z=−2  2y+6z=−1
3x2y4z=23y4z=22y+6z=1
Answered by Rasheed Soomro last updated on 20/Jun/16
3x−2y−4z=2.........(i)  3y−4z=−2.............(ii)  2y+6z=−1.............(iii)    2×(ii) : 6y−8z=−4.......(iv)  3×(iii):6y+18z=−3.......(v)  (iv)−(v) : −26z=−1⇒z=(1/(26))  Substituting z=(1/(26))  in  (ii)  3y−4((1/(26)))=−2⇒3y=−2+(2/(13))=−((24)/(13))⇒y=−((24)/(39))  Substituting values of y and z in  (i)  3x−2(−((24)/(39)))−4((1/(26)))=2  3x+((48)/(39))−(2/(13))=2⇒117x+48−6=78  x=((78−42)/(117))=((36)/(117))=(4/(13))⇒x=(4/(13))
3x2y4z=2(i)3y4z=2.(ii)2y+6z=1.(iii)2×(ii):6y8z=4.(iv)3×(iii):6y+18z=3.(v)(iv)(v):26z=1z=126Substitutingz=126in(ii)3y4(126)=23y=2+213=2413y=2439Substitutingvaluesofyandzin(i)3x2(2439)4(126)=23x+4839213=2117x+486=78x=7842117=36117=413x=413

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