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4-x-1-2x-x-2-1-2-x-1-6-1-x-2-

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Question Number 4502 by #na last updated on 02/Feb/16
(4/(x−1))−((2x)/(x^2 +1))−(2/(x+1))+(6/(1−x^2 ))
4x−1−2xx2+1−2x+1+61−x2
Answered by Rasheed Soomro last updated on 02/Feb/16
(4/(x−1))−((2x)/(x^2 +1))−(2/(x+1))−(6/((x−1)(x+1))) ((4(x+1)(x^2 +1)−2x(x−1)(x+1)−2(x−1)(x^2 +1)−6(x^2 +1))/((x−1)(x+1)(x^2 +1))) ((4(x^3 +x^2 +x+1)−2x(x^2 −1)−2(x^3 −x^2 +x−1)−6(x^2 +1))/((x−1)(x+1)(x^2 +1))) ((4x^3 +4x^2 +4x+4−2x^3 +2x−2x^3 +2x^2 −2x+2−6x^2 −6)/((x−1)(x+1)(x^2 +1))) =((4x)/((x−1)(x+1)(x^2 +1)))
4x−1−2xx2+1−2x+1−6(x−1)(x+1)4(x+1)(x2+1)−2x(x−1)(x+1)−2(x−1)(x2+1)−6(x2+1)(x−1)(x+1)(x2+1)4(x3+x2+x+1)−2x(x2−1)−2(x3−x2+x−1)−6(x2+1)(x−1)(x+1)(x2+1)4x3+4x2+4x+4−2x3+2x−2x3+2x2−2x+2−6x2−6(x−1)(x+1)(x2+1)=4x(x−1)(x+1)(x2+1)

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