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4ctg-3-x-5ctg-2-x-7ctgx-e-x-dx-

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Question Number 140241 by mathdanisur last updated on 05/May/21
∫(4ctg^3 x−5ctg^2 x+7ctgx)e^x dx=?
$$\int\left(\mathrm{4}{ctg}^{\mathrm{3}} {x}−\mathrm{5}{ctg}^{\mathrm{2}} {x}+\mathrm{7}{ctgx}\right){e}^{{x}} {dx}=? \\ $$

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