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4e-x-6e-x-9e-x-4e-x-dx-




Question Number 569 by userid1 last updated on 28/Jan/15
∫ ((4e^x +6e^(−x) )/(9e^x −4e^(−x) )) dx
$$\int\:\frac{\mathrm{4}{e}^{{x}} +\mathrm{6}{e}^{−{x}} }{\mathrm{9}{e}^{{x}} −\mathrm{4}{e}^{−{x}} }\:{dx} \\ $$

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