Question Number 68316 by 9102176137086 last updated on 08/Sep/19
$$\int\left(\mathrm{4sin}\:\mathrm{3}{x}+\frac{{e}^{\mathrm{4}{x}} }{\mathrm{4}}\right) \\ $$
Commented by mathmax by abdo last updated on 08/Sep/19
$$=\mathrm{4}\int\:{sin}\left(\mathrm{3}{x}\right){dx}\:+\frac{\mathrm{1}}{\mathrm{4}}\int\:{e}^{\mathrm{4}{x}} {dx}\:+{c} \\ $$$$=−\frac{\mathrm{4}}{\mathrm{3}}{cos}\left(\mathrm{3}{x}\right)\:+\frac{\mathrm{1}}{\mathrm{16}}{e}^{\mathrm{4}{x}} \:+{c}\:. \\ $$