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4x-2-5-2x-2-4-dx-x-0-




Question Number 4594 by alimyao last updated on 10/Feb/16
∫4x^2  − (5/(2x^(−2) )) + 4  dx, x≠0
4x252x2+4dx,x0
Answered by FilupSmith last updated on 10/Feb/16
=4∫x^2 dx−(5/2)∫x^2 dx+4∫dx  =(4/3)x^3 −(5/6)x^3 +4x+c  =(1/2)x^3 +4x+c
=4x2dx52x2dx+4dx=43x356x3+4x+c=12x3+4x+c

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