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8x-3-6x-1-0-Solves-equation-x-1-x-2-




Question Number 11661 by @ANTARES_VY last updated on 29/Mar/17
8x^3 −6x+1=0.  Solves...  equation  x_1 =?     x_2 =?
8x36x+1=0.Solvesequationx1=?x2=?
Answered by Joel576 last updated on 29/Mar/17
8x^3  − 6x + 2 = 0  ⇒ (x + 1)(8x^2  − 8x + 2) = 0  ⇒ x + 1 = 0     or    8x^2  − 8x + 2 = 0     • x + 1 = 0      x = −1  • 2(4x^2  − 4x + 1) = 0     (2x − 1)^2  = 0      x = (1/2)
8x36x+2=0(x+1)(8x28x+2)=0x+1=0or8x28x+2=0x+1=0x=12(4x24x+1)=0(2x1)2=0x=12
Commented by @ANTARES_VY last updated on 29/Mar/17
?????
?????
Commented by @ANTARES_VY last updated on 29/Mar/17
?????
?????
Commented by @ANTARES_VY last updated on 29/Mar/17
?????
?????
Commented by Joel576 last updated on 30/Mar/17
Hmm, before that you wrote  8x^3  − 6x + 2 = 0
Hmm,beforethatyouwrote8x36x+2=0

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