Question Number 5029 by love math last updated on 04/Apr/16
$${a}\:−\:\frac{\mathrm{2}\:{log}_{\mathrm{12}} \left(\mathrm{8}−{a}\right)+\frac{\mathrm{1}}{{log}_{\mathrm{2}{a}} \mathrm{12}}+\:{log}_{\mathrm{7}+{a}} \mathrm{1}.\mathrm{6}}{{log}_{\mathrm{15}−{a}} \mathrm{2}\:+\:{log}_{\mathrm{10}} {a}} \\ $$$$ \\ $$$${Simplify} \\ $$