Menu Close

A-and-B-can-do-a-job-in-10-days-and-5-days-respectively-They-worked-together-for-two-days-after-which-B-was-replaced-by-C-and-the-work-was-finished-in-the-next-three-days-How-long-will-C-alone-ta




Question Number 136063 by liberty last updated on 18/Mar/21
  A and B can do a job in 10 days and 5 days, respectively. They worked together for two days, after which B was replaced by C and the work was finished in the next three days. How long will C alone take to finish 40% of the job?
A and B can do a job in 10 days and 5 days, respectively. They worked together for two days, after which B was replaced by C and the work was finished in the next three days. How long will C alone take to finish 40% of the job?
Answered by nadovic last updated on 18/Mar/21
A′s Rate of work = (1/(10))  B′s Rate of work = (1/5)  Combined Rate of work = (1/(10)) + (1/5)                                                     = (3/(10))  ∴ A and B would complete the work       together in ((10)/3) days.  But B was replaced after 2 days.  Now,  (2/((10/3))) ×100= 60%    So A and B finished 60% of the job   and A and C will work on the 40% left  which they finished together in 3 days.  ⇒  it will take A 4 days to finish 40%          of the job, working alone.    Suppose C can finish the remaining  40% alone in x days, then                   ((0.4)/x)  +  ((0.4)/4)  =  ((0.4)/3)                   x  =  12 days   Hence, C can finish 40% of the work   alone in 12 days.
AsRateofwork=110BsRateofwork=15CombinedRateofwork=110+15=310AandBwouldcompletetheworktogetherin103days.ButBwasreplacedafter2days.Now,2(10/3)×100=60%SoAandBfinished60%ofthejobandAandCwillworkonthe40%leftwhichtheyfinishedtogetherin3days.itwilltakeA4daystofinish40%ofthejob,workingalone.SupposeCcanfinishtheremaining40%aloneinxdays,then0.4x+0.44=0.43x=12daysHence,Ccanfinish40%oftheworkalonein12days.
Commented by bramlexs22 last updated on 18/Mar/21
waw..=thanks
waw..=thanks
Answered by mr W last updated on 18/Mar/21
say A needs a days for the whole job,  B needs b days, C needs c days.  given: a=10, b=5  in two days A and B did  2×((1/(10))+(1/5))=(3/5)  in three days A and C did the rest:  3×((1/(10))+(1/c))=1−(3/5)  ⇒c=30  C needs 30 days to do the whole job.  to do 40% of the job, C needs   0.4×30=12 days
sayAneedsadaysforthewholejob,Bneedsbdays,Cneedscdays.given:a=10,b=5intwodaysAandBdid2×(110+15)=35inthreedaysAandCdidtherest:3×(110+1c)=135c=30Cneeds30daystodothewholejob.todo40%ofthejob,Cneeds0.4×30=12days
Commented by otchereabdullai@gmail.com last updated on 18/Mar/21
i like it!
ilikeit!
Commented by bramlexs22 last updated on 18/Mar/21
very simple
verysimple

Leave a Reply

Your email address will not be published. Required fields are marked *