a-b-c-a-a-ac-c-a-b-b-b-bc-a-2-b-c-3-a-D-b-2-b-D-a-2-a-b-D-c-D-ab-D-c-D-ab-c-abc-a-b-c-D-D-abc-abc-D-abc-D-a-2-b-Dab-2-a-b-b-D-a-b-D-1-cot-1-a-b-

Question Number 6725 by Danilka last updated on 16/Jul/16

a + b = c

a + a = a c

c - a = b

b + b = b c

a^{2} + b = c^{3}

a + D = b^{2}

b + D = a^{2}

a^{'} b^{'} + D = c^{'} D

a b + D = c_{D}

a b + c = a b c

a^{'} b^{'} c^{'} + D = D_{a b c}

a b c + D = {a b c}_{D}

a^{2} + b^{\pm} = {D a b}^{\pm 2}

\sqrt{a^{b} + b^{+_{-}}} = D^{\pm}

\sqrt[\partial]{\frac{a}{b} + D} = \cot^{- 1} a^{'} b^{'}

Commented by prakash jain last updated on 16/Jul/16

? ? ?