Question Number 6725 by Danilka last updated on 16/Jul/16
$${a}+{b}={c} \\ $$$${a}+{a}={ac} \\ $$$${c}−{a}={b} \\ $$$${b}+{b}={bc} \\ $$$${a}^{\mathrm{2}} +{b}={c}^{\mathrm{3}} \\ $$$${a}+{D}={b}^{\mathrm{2}} \\ $$$${b}+{D}={a}^{\mathrm{2}} \\ $$$${a}'{b}'+{D}={c}'{D} \\ $$$${ab}+{D}={c}_{{D}} \\ $$$${ab}+{c}={abc} \\ $$$${a}'{b}'{c}'+{D}={D}_{{abc}} \\ $$$${abc}+{D}={abc}_{{D}} \\ $$$${a}^{\mathrm{2}} +{b}^{\pm} ={Dab}^{\pm\mathrm{2}} \\ $$$$\sqrt{{a}^{{b}} +{b}^{+_{−} } }={D}^{\pm} \\ $$$$\sqrt[{\partial}]{\frac{{a}}{{b}}+{D}}=\mathrm{cot}^{−\mathrm{1}} {a}'{b}' \\ $$
Commented by prakash jain last updated on 16/Jul/16
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