a-b-c-a-b-1-2-a-b-c-b-c-1-2-a-b-c-a-c-1-a-b-c- Tinku Tara June 3, 2023 Algebra 0 Comments FacebookTweetPin Question Number 10067 by konen last updated on 22/Jan/17 a×b×ca+b=−12a×b×cb+c=12a×b×ca+c=1⇒a×b×c=? Answered by mrW1 last updated on 22/Jan/17 letu=a×b×c⇒a+b=−2u…(i)⇒b+c=2u…(ii)⇒a+c=u…(iii)(ii)−(iii):b−a=u…(iv)(i)+(iv):2b=−ub=−u2c=2u−b=2u+u2=5u2a=−2u−b=−2u+u2=−3u2u=a×b×c=(−3u2)×(−u2)×(5u2)=158u3(158u2−1)u=0u≠0⇒158u2−1=0u2=815⇒a×b×c=u=±815=±2215 Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: I-0-x-n-1-x-1-x-n-3-1-dx-Next Next post: If-2x-2-mxy-3y-2-5y-2-have-two-rational-factor-then-find-m- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.