A-body-starts-from-rest-and-move-with-uniform-acceleration-of-6m-s-2-what-distance-does-it-covered-in-the-3rd-seconds-

Question Number 9637 by tawakalitu last updated on 22/Dec/16

A body starts from rest and move with

uniform acceleration of 6 m / s^{2} . what

distance does it covered in the 3 rd seconds .

Answered by ridwan balatif last updated on 22/Dec/16

O \to a = 6 m / s^{2} O

∣ - - - - - - - - - - - - - - ∣

t = 0 s t = 3 s

S = Vo . t + \frac{1}{2} a . t^{2}

S = 0.3 + \frac{1}{2} . 6 . 3^{2}

S = 27 m

Commented by tawakalitu last updated on 22/Dec/16

Thanks so much sir . God bless you .

Answered by mrW last updated on 22/Dec/16

total distance in the first 2 seconds :

s_{1} = \frac{1}{2} \times 6 \times 2^{2} = 12 m

total distance in the first 3 seconds :

s_{2} = \frac{1}{2} \times 6 \times 3^{2} = 27 m

the distance in the 3 rd second :

27 - 12 = 15 m

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