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A-coil-of-inductance-0-12Hz-and-resistance-4-is-connected-across-a-240-v-50-Hz-is-supplied-Calculate-the-current-on-the-load-pi-3-142-




Question Number 12683 by tawa last updated on 29/Apr/17
A coil of inductance 0.12Hz and resistance 4 Ω is connected across a 240 v,   50 Hz is supplied . Calculate the current on the load (π = 3.142).
Acoilofinductance0.12Hzandresistance4Ωisconnectedacrossa240v,50Hzissupplied.Calculatethecurrentontheload(π=3.142).
Answered by ajfour last updated on 29/Apr/17
I_(rms) =(E_(rms) /Z)  Z=(√(R^2 +4π^2 ν^2 L^2 ))      =(√(16+4(9.86)(2500)(0.12)^2 ))      =37.9 Ω  I_(rms) =((240V)/(37.9Ω)) =6.33 A .
Irms=ErmsZZ=R2+4π2ν2L2=16+4(9.86)(2500)(0.12)2=37.9ΩIrms=240V37.9Ω=6.33A.
Commented by tawa last updated on 29/Apr/17
God bless you sir.
Godblessyousir.

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