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A-committee-of-3-members-is-to-be-formed-from-8-members-Find-the-number-of-committees-that-can-be-formed-if-two-particular-club-members-cannot-both-be-in-a-committee-




Question Number 138748 by physicstutes last updated on 17/Apr/21
A committee of 3 members is to be formed from 8 members.  Find the number of committees that can be formed if two particular  club members cannot both be in a committee
Acommitteeof3membersistobeformedfrom8members.Findthenumberofcommitteesthatcanbeformediftwoparticularclubmemberscannotbothbeinacommittee
Answered by mr W last updated on 17/Apr/21
C_3 ^8 −C_1 ^6 =50
C38C16=50
Commented by physicstutes last updated on 17/Apr/21
sir please why the ^6 C_1  part?
sirpleasewhythe6C1part?
Commented by mr W last updated on 17/Apr/21
to select 3 from 8 persons there are  totally C_3 ^8  ways.  if two particular persons are in the  committee, to select the third person  from the rest 6 persons, there are  C_1 ^6  ways.  since these two particular persons  should not be both in the committee,  so we have only C_3 ^8 −C_1 ^6  ways.
toselect3from8personstherearetotallyC38ways.iftwoparticularpersonsareinthecommittee,toselectthethirdpersonfromtherest6persons,thereareC16ways.sincethesetwoparticularpersonsshouldnotbebothinthecommittee,sowehaveonlyC38C16ways.
Commented by mr W last updated on 17/Apr/21
certainly you can also solve like this:  say the two particular persons are  A and B.  1) both A and B are not in committee  we select all three members from the  other 6 persons, there are C_3 ^6  ways.  2) A is in committe  we select other two members from  the other 6 persons, there are C_2 ^6  ways.  3) B is in committe  we select other two members from  the other 6 persons, there are C_2 ^6  ways.  totally: there are  C_3 ^6 +2×C_2 ^6 =50 ways.
certainlyyoucanalsosolvelikethis:saythetwoparticularpersonsareAandB.1)bothAandBarenotincommitteeweselectallthreemembersfromtheother6persons,thereareC36ways.2)Aisincommitteweselectothertwomembersfromtheother6persons,thereareC26ways.3)Bisincommitteweselectothertwomembersfromtheother6persons,thereareC26ways.totally:thereareC36+2×C26=50ways.
Commented by physicstutes last updated on 18/Apr/21
that was brilliant sir. Thanks
thatwasbrilliantsir.Thanks

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