A-manometer-wire-of-lenght-60-cm-is-maintained-under-a-tension-of-value-20V-and-an-a-c-is-passed-through-the-wire-If-the-density-of-the-wire-is-4000kgm-3-and-it-diamerter-is-2mm-Calculate-the-f

Question Number 10639 by Saham last updated on 21/Feb/17

A manometer wire of lenght 60 cm is maintained under

a tension of value 20 V and an a . c is passed through

the wire . If the density of the wire is {4000 kgm}^{- 3} and it

diamerter is 2 mm . Calculate the frequency of the a . c

Commented by Saham last updated on 21/Feb/17

please help with this too . God bless you .

Commented by mrW1 last updated on 21/Feb/17

a t e n s i o n o f 20 V \dots w h a t d o e s i t m e a n ?

a t e n s i o n i s a f o r c e, i t s u n i t s h o u l d b e

N e w t o n .

Commented by Saham last updated on 21/Feb/17

please use newton sir .

Answered by mrW1 last updated on 21/Feb/17

f = \frac{1}{2 L} \sqrt{\frac{T}{μ}}

μ = \frac{π d^{2} ρ}{4}

f - f r e q u e n c y (H z)

L - l e n g t h o f w i r e (m)

T - t e n s i o n i n w i r e (N)

μ - m a s s o f w i r e (k g / m)

d - d i a m e t e r o f w i r e (m)

ρ - d e n s i t y o f w i r e (k g / m^{3})

\Rightarrow f = \frac{1}{d L} \sqrt{\frac{T}{π ρ}} = \frac{1}{0.002 \times 0.6} \sqrt{\frac{20}{4000 π}} = 33 H z

i^{'} m n o t s u r e i f t h i s i s t h e r i g h t a n s w e r

t o y o u r q u e s t i o n .

Commented by Saham last updated on 21/Feb/17

Thank you sir . God bless you .

Commented by Saham last updated on 21/Feb/17

i will confirm

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