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a-n-1-2-3-4-5-n-n-1-mod-2-a-n-1-2-3-4-5-6-n-n-0-mod-2-lim-n-a-n-1-

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Question Number 348 by 123456 last updated on 23/Dec/14
a_n =1−(2/(3−(4/(5−n)))),n≡1(mod 2) a_n =1−(2/(3−(4/(5−(6/n))))),n≡0(mod 2) lim_(n→∞) a_n =^? 1
an=1−23−45−n,n≡1(mod2)an=1−23−45−6n,n≡0(mod2)limn→∞an=?1
Commented by 123456 last updated on 23/Dec/14
a_1 =1 a_2 =1−2=−1 a_3 =1−(2/3)=(1/3) a_4 =1−(2/(3−4))=1+2=3 a_5 =1−(2/(3−(4/5)))=1−(2/((11)/5))=1−((10)/(11))=(1/(11))
a1=1a2=1−2=−1a3=1−23=13a4=1−23−4=1+2=3a5=1−23−45=1−2115=1−1011=111

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