Menu Close

a-n-m-m-n-0-a-n-1-m-2-n-gt-0-n-0-mod-2-a-n-2-m-1-nn-n-gt-0-n-1-mod-2-m-0-a-m-1-n-1-a-n-2-m-2-n-gt-0-n-1-mod-2-m-gt-0-evaluate-a-7-5-

Tinku Tara
Pin




Question Number 291 by 123456 last updated on 25/Jan/15
a(n,m)= { (m,(n≤0)),((a(n−1,m+2)),(n>0∧n≡0(mod 2))),((a(n−2,m−1)+nn),(n>0∧n≡1(mod 2)∧m≤0)),((a(m−1,n−1)+a(n−2,m−2)),(n>0∧n≡1(mod 2)∧m>0)) :} evaluate a(7,5)
a(n,m)={mn⩽0a(n−1,m+2)n>0∧n≡0(mod2)a(n−2,m−1)+nnn>0∧n≡1(mod2)∧m⩽0a(m−1,n−1)+a(n−2,m−2)n>0∧n≡1(mod2)∧m>0evaluatea(7,5)
Answered by prakash jain last updated on 19/Dec/14
a(7,5)=a(4,6)+a(5,3) =a(3,8)+a(2,4)+a(3,1) =a(7,2)+a(1,6)+a(1,6)+a(0,2)+a(1,−1) a(1,6)=a(5,0)+a(−1,4) =a(3,−1)+25+4 =a(1,−2)+6+25+4 =a(−1,−3)+1+6+25+4 =−3+1+6+25+4=33 a(0,2)=2 a(1,−1)=a(−1,−3)+1=−3+1=2 a(7,2)=a(1,6)+a(5,0) =a(5,0)+a(−1,4)+a(5,0) =29+4+29=62 a(7,5)=62+33+33+2+2=132
a(7,5)=a(4,6)+a(5,3)=a(3,8)+a(2,4)+a(3,1)=a(7,2)+a(1,6)+a(1,6)+a(0,2)+a(1,−1)a(1,6)=a(5,0)+a(−1,4)=a(3,−1)+25+4=a(1,−2)+6+25+4=a(−1,−3)+1+6+25+4=−3+1+6+25+4=33a(0,2)=2a(1,−1)=a(−1,−3)+1=−3+1=2a(7,2)=a(1,6)+a(5,0)=a(5,0)+a(−1,4)+a(5,0)=29+4+29=62a(7,5)=62+33+33+2+2=132

Pin