A-point-T-divides-a-line-AB-internally-in-the-ratio-5-2-Given-that-A-is-4-10-and-B-is-10-3-find-the-coordinates-of-T-

Question Number 66746 by John Kaloki Musau last updated on 20/Aug/19

A p o i n t T d i v i d e s a l i n e A B i n t e r n a l l y i n t h e r a t i o 5 : 2 . G i v e n t h a t A i s (- 4, 10) a n d B i s (10, 3), f i n d t h e c o o r d i n a t e s o f T .

Answered by mr W last updated on 19/Aug/19

x_{T} = x_{A} + \frac{5}{7} (x_{B} - x_{A}) = - 4 + \frac{5}{7} (10 + 4) = 6

y_{T} = y_{A} + \frac{5}{7} (y_{B} - y_{A}) = 10 + \frac{5}{7} (3 - 10) = 5

\Rightarrow T (6, 5)

Commented by John Kaloki Musau last updated on 19/Aug/19

correct

Answered by Rio Michael last updated on 19/Aug/19

T (x, y) = (\frac{μ x_{1} + λ x_{2}}{μ + λ}, \frac{μ y_{1} + λ y_{2}}{μ + λ}) \dots \dots . . i n t e r n a l d i v i s i o n

T (x, y) = (\frac{5 (- 4) + 2 (10)}{5 + 2}, \frac{5 (10) + 2 (3)}{5 + 2})

T (x, y) = (0, \frac{56}{7})

Commented by mr W last updated on 20/Aug/19

p l e a s e c h e c k s i r :

i t s h o u l d b e

T (x, y) = (\frac{2 (- 4) + 5 (10)}{5 + 2}, \frac{2 (10) + 5 (3)}{5 + 2})

T (x, y) = (6, 5)

Commented by mr W last updated on 20/Aug/19

T (x, y) = (\frac{μ x_{2} + λ x_{1}}{μ + λ}, \frac{μ y_{2} + λ y_{1}}{μ + λ}) \dots \dots . . i n t e r n a l d i v i s i o n

Commented by Rio Michael last updated on 21/Aug/19

y o u r r i g h t s i r t h a n k s