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Question Number 9125 by tawakalitu last updated on 20/Nov/16

A polygon has two interior angles of 120 ° each

and the others are each 150 ° . calculate

(a) The number of sides of the polygon .

(b) The sum of the interior angles .

Answered by mrW last updated on 20/Nov/16

T h e s u m o f t h e i n t e r i o r a n g l e s o f

a p o l y g o n w i t h n s i d e s i s (n - 2) \times 180 d e g r e e s .

2 \times 120 + (n - 2) \times 150 = (n - 2) \times 180

240 + 150 n - 300 = 180 n - 360

30 n = 300

n = 10

{I t}^{'} s a p o l y g o n w i t h 10 s i d e s .

T h e s u m o f i t s i n t e r i o r a n g l e s :

(10 - 2) \times 180 = 1440 d e g r e e s

Commented by tawakalitu last updated on 20/Nov/16

Thank you very much sir . God bless you .