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Question Number 12610 by tawa last updated on 26/Apr/17
A steam engine of efficiency 50% burns a 1g of coal to produce 10000J  of energy. if it burns 20g per sec, calculate the output power.
$$\mathrm{A}\:\mathrm{steam}\:\mathrm{engine}\:\mathrm{of}\:\mathrm{efficiency}\:\mathrm{50\%}\:\mathrm{burns}\:\mathrm{a}\:\mathrm{1g}\:\mathrm{of}\:\mathrm{coal}\:\mathrm{to}\:\mathrm{produce}\:\mathrm{10000J} \\ $$$$\mathrm{of}\:\mathrm{energy}.\:\mathrm{if}\:\mathrm{it}\:\mathrm{burns}\:\mathrm{20g}\:\mathrm{per}\:\mathrm{sec},\:\mathrm{calculate}\:\mathrm{the}\:\mathrm{output}\:\mathrm{power}. \\ $$
Answered by mrW1 last updated on 27/Apr/17
P=0.5×20×10000=100000 Watt=100 kW
$${P}=\mathrm{0}.\mathrm{5}×\mathrm{20}×\mathrm{10000}=\mathrm{100000}\:{Watt}=\mathrm{100}\:{kW} \\ $$
Commented by tawa last updated on 27/Apr/17
God bless you sir.
$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}. \\ $$

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