Question Number 10687 by Saham last updated on 22/Feb/17
$$\mathrm{Abbey}\:\mathrm{and}\:\mathrm{mary}\:\mathrm{carry}\:\mathrm{a}\:\mathrm{uniform}\:\mathrm{log}\:\mathrm{of}\:\mathrm{length}\:\mathrm{10m}\:\mathrm{and}\:\mathrm{weight}\:\mathrm{100N}. \\ $$$$\mathrm{Abbey}\:\mathrm{is}\:\mathrm{1m}\:\mathrm{from}\:\mathrm{one}\:\mathrm{end}\:\mathrm{and}\:\mathrm{mary}\:\mathrm{is}\:\mathrm{2m}\:\mathrm{from}\:\mathrm{the}\:\mathrm{other}\:\mathrm{end}.\:\mathrm{what} \\ $$$$\mathrm{weight}\:\mathrm{does}\:\mathrm{abbey}\:\mathrm{and}\:\mathrm{mary}\:\mathrm{support}. \\ $$
Answered by mrW1 last updated on 22/Feb/17
$${weight}\:{is}\:{in}\:{the}\:{middle}\:{of}\:{log}. \\ $$$${distance}\:{of}\:{abbey}\:{to}\:{weight}:\:\mathrm{5}−\mathrm{1}=\mathrm{4}{m} \\ $$$${distance}\:{of}\:{mary}\:{to}\:{weight}:\:\mathrm{5}−\mathrm{2}=\mathrm{3}{m} \\ $$$${weight}\:{which}\:{abbey}\:{carries}:\:\frac{\mathrm{3}}{\mathrm{3}+\mathrm{4}}×\mathrm{100}=\frac{\mathrm{300}}{\mathrm{7}}\:=\mathrm{42}.\mathrm{9}\:{N} \\ $$$${weight}\:{which}\:{mary}\:{carries}:\:\frac{\mathrm{4}}{\mathrm{3}+\mathrm{4}}×\mathrm{100}=\frac{\mathrm{400}}{\mathrm{7}}=\mathrm{57}.\mathrm{1}\:{N} \\ $$$$ \\ $$
Commented by Saham last updated on 22/Feb/17
$$\mathrm{i}\:\mathrm{mistakenly}\:\mathrm{flagged}.\: \\ $$$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}. \\ $$$$\mathrm{I}\:\mathrm{really}\:\mathrm{appreciate}\:\mathrm{your}\:\mathrm{effort}\:\mathrm{all}\:\mathrm{the}\:\mathrm{time}. \\ $$