An-aqeous-solution-of-tetraoxosulphate-IV-has-a-density-of-1-80-g-cm-3-and-98-purity-level-what-volume-of-this-solution-must-be-diluted-to-give-250-cm-3-of-0-500-mol-dm-3-H-2-SO-4-solution-

Question Number 6583 by Tawakalitu. last updated on 04/Jul/16

A n a q e o u s s o l u t i o n o f t e t r a o x o s u l p h a t e (I V) h a s a d e n s i t y

o f 1.80 g / {c m}^{3} a n d 98 % p u r i t y l e v e l . w h a t v o l u m e o f t h i s

s o l u t i o n m u s t b e d i l u t e d t o g i v e 250 {c m}^{3} o f 0.500 m o l / {d m}^{3}

H_{2} {S O}_{4} s o l u t i o n ?

Answered by sandy_suhendra last updated on 04/Jul/16

M_{1} = \frac{1.8 \times 98 \times 10}{98} = 18 m o l / {d m}^{3}

M_{2} = 0.5 m o l / {d m}^{3}

V_{2} = 250 {c m}^{3}

V_{1} = ?

V_{1} \times M_{1} = V_{2} \times M_{2}

V_{1} \times 18 = 250 \times 0.5

V_{1} = 6.94 {c m}^{3}

Commented by sandy_suhendra last updated on 04/Jul/16

M_{1} = \frac{d e n s i t y \times % p u r i t y \times 10}{M r}

Commented by Tawakalitu. last updated on 05/Jul/16

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