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An-electron-moves-in-a-vacuum-between-two-electrode-having-a-p-d-of-3000v-calculate-the-velocity-acquired-by-the-electon-if-the-ratio-of-its-charge-to-mass-is-1-8-10-11-Ckg-1-




Question Number 10236 by Tawakalitu ayo mi last updated on 30/Jan/17
An electron moves in a vacuum between  two electrode having a p.d of 3000v, calculate  the velocity acquired by the electon if the ratio  of its charge to mass is 1.8×10^(11) Ckg^(−1)
$$\mathrm{An}\:\mathrm{electron}\:\mathrm{moves}\:\mathrm{in}\:\mathrm{a}\:\mathrm{vacuum}\:\mathrm{between} \\ $$$$\mathrm{two}\:\mathrm{electrode}\:\mathrm{having}\:\mathrm{a}\:\mathrm{p}.\mathrm{d}\:\mathrm{of}\:\mathrm{3000v},\:\mathrm{calculate} \\ $$$$\mathrm{the}\:\mathrm{velocity}\:\mathrm{acquired}\:\mathrm{by}\:\mathrm{the}\:\mathrm{electon}\:\mathrm{if}\:\mathrm{the}\:\mathrm{ratio} \\ $$$$\mathrm{of}\:\mathrm{its}\:\mathrm{charge}\:\mathrm{to}\:\mathrm{mass}\:\mathrm{is}\:\mathrm{1}.\mathrm{8}×\mathrm{10}^{\mathrm{11}} \mathrm{Ckg}^{−\mathrm{1}} \\ $$
Answered by ridwan balatif last updated on 31/Jan/17
Potensial energy of eletric=kinetik energy of electron  e.V=(1/2)mv^2   (e/m)=(v^2 /(2V))  v=(√((e/m)×2V))  (e/m)=1.8×10^(11) Ckg^(−1)   V=3000volt  v=(√(1.8×10^(11) ×2×3000))  v≈3.28×10^7 m/s
$$\mathrm{Potensial}\:\mathrm{energy}\:\mathrm{of}\:\mathrm{eletric}=\mathrm{kinetik}\:\mathrm{energy}\:\mathrm{of}\:\mathrm{electron} \\ $$$$\mathrm{e}.\mathrm{V}=\frac{\mathrm{1}}{\mathrm{2}}\mathrm{m}{v}^{\mathrm{2}} \\ $$$$\frac{\mathrm{e}}{\mathrm{m}}=\frac{{v}^{\mathrm{2}} }{\mathrm{2V}} \\ $$$${v}=\sqrt{\frac{\mathrm{e}}{\mathrm{m}}×\mathrm{2V}} \\ $$$$\frac{\mathrm{e}}{\mathrm{m}}=\mathrm{1}.\mathrm{8}×\mathrm{10}^{\mathrm{11}} \mathrm{Ckg}^{−\mathrm{1}} \\ $$$$\mathrm{V}=\mathrm{3000volt} \\ $$$${v}=\sqrt{\mathrm{1}.\mathrm{8}×\mathrm{10}^{\mathrm{11}} ×\mathrm{2}×\mathrm{3000}} \\ $$$${v}\approx\mathrm{3}.\mathrm{28}×\mathrm{10}^{\mathrm{7}} \mathrm{m}/\mathrm{s} \\ $$
Commented by Tawakalitu ayo mi last updated on 31/Jan/17
i really appreciate sir. God bless you.
$$\mathrm{i}\:\mathrm{really}\:\mathrm{appreciate}\:\mathrm{sir}.\:\mathrm{God}\:\mathrm{bless}\:\mathrm{you}. \\ $$

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