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arcsin-ln-3-cot4-x-4-1-19-5-




Question Number 132107 by weltr last updated on 11/Feb/21
(arcsin∣ln^3 (cot4 − x)∣ + 4!)^(1/(19))  = 5
(arcsinln3(cot4x)+4!)119=5
Answered by Olaf last updated on 11/Feb/21
(arcsin∣ln^3 (cot4−x)∣+4!)^(1/(19))  = 5  arcsin∣ln^3 (cot4−x)∣ = 5^(19) −24 > (π/2)  S_R  = ∅
(arcsinln3(cot4x)+4!)119=5arcsinln3(cot4x)=51924>π2SR=

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