Question Number 132195 by aurpeyz last updated on 12/Feb/21
$${Aspherical}\:{satelite}\:{orbiting}\:{Earth}\:{is} \\ $$$${lighted}\:{on}\:{one}\:{side}\:{by}\:{the}\:{sun}\:{with}\:{intensity} \\ $$$$\mathrm{340}{W}/{m}^{\mathrm{2}} .\:{If}\:{the}\:{radius}\:{of}\:{the}\: \\ $$$${satelite}\:{is}\:\mathrm{1}{m}.\:{what}\:{power}\:{is}\: \\ $$$${incident}\:{upon}\:{it}? \\ $$
Answered by ajfour last updated on 12/Feb/21
$${P}_{{incident}} ={I}_{{incident}} \left({A}_{{projected}} \right) \\ $$$${P}_{{in}} =\left(\frac{\mathrm{340}{W}}{{m}^{\mathrm{2}} }\right)\left[\pi\left(\mathrm{1}{m}\right)^{\mathrm{2}} \right] \\ $$$${P}_{{in}} =\mathrm{340}\pi\:{W}\:\approx\:\mathrm{1068}.\mathrm{1415}{W} \\ $$
Commented by aurpeyz last updated on 12/Feb/21
$${Area}\:{of}\:{sphere}\:{is}\:{supposed}\:{to}\:{be} \\ $$$$\mathrm{4}\pi{r}^{\mathrm{2}} \:? \\ $$
Commented by ajfour last updated on 12/Feb/21
$${but}\:{projected}\:{area}\:{of}\:{the} \\ $$$${sphere}\:{is}\:{that}\:{of}\:{a}\:{disc}\:{of} \\ $$$${the}\:{same}\:{radius},\:{and}\:{power} \\ $$$${received}\:{by}\:{sphere}\:{is}\:{equal}\:{to} \\ $$$${the}\:{power}\:{received}\:{by}\:{the}\:{disc}. \\ $$
Commented by aurpeyz last updated on 12/Feb/21
$${thank}\:{you}\:{Sir}.\:{youre}\:{correct} \\ $$