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Assuming-it-rained-at-a-constant-rate-and-the-rain-fell-at-angle-to-the-ground-see-diagram-determine-if-walking-or-running-causes-you-to-get-more-less-wet-or-of-it-makes-no-difference-for-1-




Question Number 11902 by FilupS last updated on 04/Apr/17
Assuming it rained at a constant rate,  and the rain fell at angle θ to the ground  (see diagram), determine if walking or  running causes you to get more/less wet,  or of it makes no difference for:     1.   θ=90°  (downwards)  2. θ<90°  (the rain is moving on the           same direction as you)  3. θ>90°  (the rain is moving/blowing           into you)
Assumingitrainedataconstantrate,andtherainfellatangleθtotheground(seediagram),determineifwalkingorrunningcausesyoutogetmore/lesswet,orofitmakesnodifferencefor:1.θ=90°(downwards)2.θ<90°(therainismovingonthesamedirectionasyou)3.θ>90°(therainismoving/blowingintoyou)
Commented by FilupS last updated on 04/Apr/17
Answered by b.e.h.i.8.3.4.1.7@gmail.com last updated on 04/Apr/17
we can suppose that the human budy  like a rectangle that its dimentions are  almost about:B=25,W=65,H=180,in  centimeters.  1.θ<90 or θ>90 are the same.in this  case wet area=65×180#11700cm^2   area above sholders=(65−25)×25=1000  added area for man=2πR_1 (r_1 +2h_1 )+πR_2 (r_2 +2h_2 )=  =2×3.14×12(5+2×4)+1×3.14×4(2+2×1.5)=981+63=1043  added area for lady=2π×16(8+3×5)+2×π×10(5+3×4)=2311+1068=3379  total for man ,face to rain=  11700−1000+63=10763cm^2   total for man, back to rain=  11700−1000+981=11681cm^2   total for lady,face to rain=  11700−1000+1068=11768cm^2   total for lady ,back to rain=  11700−1000+2311=13011cm^2   2.θ=90,in this case only up side of  rectangle opposite to rain.so:  the wet area =25×65#1625cm^2   total for man=1625+(1/2)×63+(1/2)×981#2138cm^2   total for lady=1625+(1/2)×2311+(1/2)×1068#3315cm^2   Now we know that the max of wet area  in case of:θ>90^° and for lady that run  back to rain.I think running or walking are the same .excuse me,I think we should calculating areas  with much more of accuracy.
wecansupposethatthehumanbudylikearectanglethatitsdimentionsarealmostabout:B=25,W=65,H=180,incentimeters.1.θ<90orθ>90arethesame.inthisYou can't use 'macro parameter character #' in math modeareaabovesholders=(6525)×25=1000addedareaforman=2πR1(r1+2h1)+πR2(r2+2h2)==2×3.14×12(5+2×4)+1×3.14×4(2+2×1.5)=981+63=1043addedareaforlady=2π×16(8+3×5)+2×π×10(5+3×4)=2311+1068=3379totalforman,facetorain=117001000+63=10763cm2totalforman,backtorain=117001000+981=11681cm2totalforlady,facetorain=117001000+1068=11768cm2totalforlady,backtorain=117001000+2311=13011cm22.θ=90,inthiscaseonlyupsideofrectangleoppositetorain.so:You can't use 'macro parameter character #' in math modeYou can't use 'macro parameter character #' in math modeYou can't use 'macro parameter character #' in math modeNowweknowthatthemaxofwetareaincaseof:θ>90°andforladythatrunbacktorain.Ithinkrunningorwalkingarethesame.excuseme,Ithinkweshouldcalculatingareaswithmuchmoreofaccuracy.

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