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calculate-0-x-n-3-1-x-2n-dx-with-n-3-




Question Number 67530 by mathmax by abdo last updated on 28/Aug/19
calculate ∫_0 ^∞    (x^(n−3) /(1+x^(2n) ))dx  with n≥3
calculate0xn31+x2ndxwithn3
Commented by ~ À ® @ 237 ~ last updated on 29/Aug/19
let named it J  let change u=x^(2n) ⇔x=u^(1/(2n))   ⇒ dx=(1/(2n))u^((1/(2n))−1) du  J=(1/(2n)) .∫_0 ^∞  (u^((n−3)/(2n)) /(1+u)).u^((1/(2n))−1) du=(1/(2n)). ∫_0 ^∞ (u^((1/2)−(1/n)−1) /(1+u))du=(π/(2nsin((π/2)−(π/n))))=(π/(2ncos((π/n))))
letnameditJletchangeu=x2nx=u12ndx=12nu12n1duJ=12n.0un32n1+u.u12n1du=12n.0u121n11+udu=π2nsin(π2πn)=π2ncos(πn)
Commented by Abdo msup. last updated on 29/Aug/19
thanks sir.
thankssir.

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