calculate-I-0-1-1-1-e-x-dx- Tinku Tara June 3, 2023 None 0 Comments FacebookTweetPin Question Number 133964 by mathocean1 last updated on 26/Feb/21 calculateI=∫0111+exdx Answered by bobhans last updated on 26/Feb/21 ∫ex+1−ex1+exdx=x−∫ex1+exdx=x−ln(1+ex)+cI=[x−ln(1+ex)]01=1−ln(1+e)+ln(2)=1+ln(21+e)=ln(2e1+e) Answered by Olaf last updated on 26/Feb/21 I=∫01dx1+exI=∫01(1+ex1+ex−ex1+ex)dxI=[x−ln(1+ex)]01I=1−ln(1+e)+ln2I=1+ln(21+e) Answered by mathmax by abdo last updated on 26/Feb/21 I=∫01dxex+1changementex=tgivex=lnt⇒I=∫1edtt(t+1)=∫1e(1t−1t+1)dt=[ln∣tt+1∣]1e=ln(ee+1)−ln(12)=1−ln(e+1)+ln(2) Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: Question-133961Next Next post: Question-68434 Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.