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calculate-lim-x-0-ln-cosx-1-cos-2x-




Question Number 66317 by mathmax by abdo last updated on 12/Aug/19
calculate lim_(x→0)  ((ln(cosx))/(1−cos(2x)))
calculatelimx0ln(cosx)1cos(2x)
Commented by kaivan.ahmadi last updated on 12/Aug/19
≡lim_(x→0) ((ln(cosx))/(2x^2 ))=^(hop) lim_(x→0) ((−sinx)/(4xcosx))=^(hop)   lim_(x→0)  ((−cosx)/(4cosx−4xsinx))=((−1)/4)
limx0ln(cosx)2x2=hoplimx0sinx4xcosx=hoplimx0cosx4cosx4xsinx=14
Commented by mathmax by abdo last updated on 12/Aug/19
thanks sir.
thankssir.

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