Menu Close

calculate-n-1-2-n-3-n-2n-3-n-2-5n-2-




Question Number 66680 by mathmax by abdo last updated on 18/Aug/19
calculate  Σ_(n=1) ^∞     (2^n /(3^n (2n^3  +n^2 −5n +2)))
$${calculate}\:\:\sum_{{n}=\mathrm{1}} ^{\infty} \:\:\:\:\frac{\mathrm{2}^{{n}} }{\mathrm{3}^{{n}} \left(\mathrm{2}{n}^{\mathrm{3}} \:+{n}^{\mathrm{2}} −\mathrm{5}{n}\:+\mathrm{2}\right)} \\ $$
Commented by Mohamed Amine Bouguezzoul last updated on 18/Aug/19
it cannot be with n=1
$${it}\:{cannot}\:{be}\:{with}\:{n}=\mathrm{1} \\ $$
Commented by mathmax by abdo last updated on 19/Aug/19
sorry the Q is calculate Σ_(n=2) ^∞  (2^n /(3^n (2n^3  +n^2 −5n +2)))
$${sorry}\:{the}\:{Q}\:{is}\:{calculate}\:\sum_{{n}=\mathrm{2}} ^{\infty} \:\frac{\mathrm{2}^{{n}} }{\mathrm{3}^{{n}} \left(\mathrm{2}{n}^{\mathrm{3}} \:+{n}^{\mathrm{2}} −\mathrm{5}{n}\:+\mathrm{2}\right)} \\ $$

Leave a Reply

Your email address will not be published. Required fields are marked *