compare-1-log-2-pi-1-log-5-pi-and-2-

Question Number 1112 by malwaan last updated on 14/Jun/15

c o m p a r e \frac{1}{{l o g}_{2} π} + \frac{1}{{l o g}_{5} π} a n d 2

Answered by prakash jain last updated on 15/Jun/15

\log_{π} 2 + \log_{π} 5 = \log_{π} 10

10 > π^{2} \Rightarrow \log_{π} 10 > 2